Wire & Terminals
In order to keep the voltage drop in the cables as low as possible and to avoid excessive heating of the cable, a careful investigation of the required cable cross-sections is necessary. The voltage drop (loss) between the power sources and consumers must not exceed the following values.
Since the current always has a round trip by 2 cores, the conductor length (for example, the distance between the battery and the device) is twice as large as the cable length. The constant 56 = conductivity of copper.
Required section (mm²) = 2 x cable length (m) x current (A)
6 x permissible voltage drop (V)
For example, a 25W / 12V-position lamp on a 12m high mast tip
Battery cable length of up to 18m mast top.
Power consumption: 12V = 2.1A
Permissible voltage drop: max. 5% of 12V = 0.6V
You should go with the standard cross-section of 2.5 mm² / wire
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Maximum allowable voltage loss:
Navigation lights: 5% = 0.60 V on a 12 V electrical system.
Other consumers: 7% = 0.84 V on a 12 V electrical system.
The required conductor cross-section, wherein the permissible voltage drop (V) is not exceeded, is calculated using the following equation: since the current is multi-directional and it has 2 cores, the conductor length is twice as large as the cable length (the distance between the consumer and battery). The constant 56 = conductivity of copper.
The required conductor cross-section in which the permissible voltage drop (V) is not exceeded, calculated using the following equation:Navigation lights: 5% = 0.60 V on a 12 V electrical system.
Other consumers: 7% = 0.84 V on a 12 V electrical system.
The required conductor cross-section, wherein the permissible voltage drop (V) is not exceeded, is calculated using the following equation: since the current is multi-directional and it has 2 cores, the conductor length is twice as large as the cable length (the distance between the consumer and battery). The constant 56 = conductivity of copper.
Since the current always has a round trip by 2 cores, the conductor length (for example, the distance between the battery and the device) is twice as large as the cable length. The constant 56 = conductivity of copper.
Required section (mm²) = 2 x cable length (m) x current (A)
6 x permissible voltage drop (V)
For example, a 25W / 12V-position lamp on a 12m high mast tip
Battery cable length of up to 18m mast top.
Power consumption: 12V = 2.1A
Permissible voltage drop: max. 5% of 12V = 0.6V
You should go with the standard cross-section of 2.5 mm² / wire
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